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🧮 Geometric Series Sum 計算機

專業免費的 Geometric Series Sum 計算機。純前端本機毫秒級計算、零資料上傳、極致隱私保護。提供詳細公式推導、實例示範與常見問答。

即時推算結果 (Computed Output)
1,023 sum of the first 10 terms
專業公認計算模型,即時運算完畢
📜 計算歷史記錄 (試算軌跡)
尚無歷史記錄,每次點擊「計算」將在此留下試算軌跡...

What this calculator does

A geometric series is a sum of terms in which each term is found by multiplying the previous one by a fixed number called the common ratio. The sequence looks like a, ar, ar², ar³, …, ar^(n−1). This calculator finds two things at once: the nth term of the progression and the sum of its first n terms (the partial sum), given the first term a, the common ratio r, and the number of terms n.

How to use it

Enter the first term a (any real number, positive, negative, or fractional), the common ratio r, and the number of terms n (a positive whole number). Optionally choose a display precision to control how many significant digits are shown — this affects the display only, not the calculation. Press calculate to see both the nth term aₙ and the sum Sₙ.

The formula explained

The nth term is a_n = a · r^{ n-1}. For the sum, when r is not equal to 1 we use the closed form

S_n = a · ((1 - r^{ n}) ÷ (1 - r))
When r equals 1 every term is identical, so the denominator 1 - r would be zero; in that special case the sum is simply S_n = n · a. The calculator branches automatically to avoid division by zero.

Worked example

With a = 1, r = 2, n = 10: the 10th term is a_n = 1 · 2^{9} = 512. The sum is

S_n = 1 · ((1 - 2^{10}) ÷ (1 - 2)) = ((1 - 1024) ÷ (-1)) = 1023

使用注意事項與精準校對原則(6 大核心守則)

📐 1. 嚴格對齊輸入量綱與單位

輸入各項數值時請務必確認量綱(例如小時、天數、金額、百分比),避免單位不匹配引發推算偏差。

🔒 2. 純前端本機毫秒級隱私保障

所有計算邏輯 100% 在您的終端瀏覽器內完成,資料絕不上傳伺服器,嚴格守護商業與個人隱私。

📊 3. 符合公認學術與產業計算模型

演算法嚴格遵循國際通用數學公式與標準計算模型,經多重情境交叉核對,數值嚴密精確。

📋 4. 一鍵複製與免登入 PDF 匯出

支援一鍵複製推算結果字串至剪貼簿,亦可直接點擊列印按鈕輸出純淨 PDF 工作報表。

🔄 5. 多情景敏感度動態對比

建議針對極端值與多組預期情景分別試算,觀察輸出數據的波動區間,輔助做出更穩健的決策。

🛡️ 6. 專業諮詢與日常參考免責聲明

本工具運算結果供日常排程、學業研習與事前參考之用,如涉及重大法規或投資決策請諮詢持證專家。

常見問題 (FAQ)

Does this compute the infinite sum?
No. It always computes the finite partial sum of exactly n terms. When |r| < 1 the partial sum approaches \(a/(1-r)\) as n grows, but this tool never assumes an infinite number of terms.
Can the ratio be negative?
Yes. A negative r makes the terms alternate in sign, and the formula remains valid.
What if r = 0?
Then the first term contributes a and all later terms are zero, so Sₙ = a and aₙ = a only when n = 1 (otherwise 0).